(6x-+2)^2+4=28

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Solution for (6x-+2)^2+4=28 equation: 



(6x-+2)^2+4=28

We move all terms to the left:

(6x-+2)^2+4-(28)=0

We add all the numbers together, and all the variables

(+6x)^2+4-28=0

We add all the numbers together, and all the variables

(+6x)^2-24=0

We move all terms containing x to the left, all other terms to the right

(+6x)^2=24

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